Optimal. Leaf size=119 \[ \frac {33 a b (d \sec (e+f x))^{5/3}}{40 f}+\frac {3 \left (8 a^2-3 b^2\right ) d \, _2F_1\left (-\frac {1}{3},\frac {1}{2};\frac {2}{3};\cos ^2(e+f x)\right ) (d \sec (e+f x))^{2/3} \sin (e+f x)}{16 f \sqrt {\sin ^2(e+f x)}}+\frac {3 b (d \sec (e+f x))^{5/3} (a+b \tan (e+f x))}{8 f} \]
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Rubi [A]
time = 0.11, antiderivative size = 119, normalized size of antiderivative = 1.00, number of steps
used = 4, number of rules used = 4, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.160, Rules used = {3589, 3567,
3857, 2722} \begin {gather*} \frac {3 d \left (8 a^2-3 b^2\right ) \sin (e+f x) (d \sec (e+f x))^{2/3} \, _2F_1\left (-\frac {1}{3},\frac {1}{2};\frac {2}{3};\cos ^2(e+f x)\right )}{16 f \sqrt {\sin ^2(e+f x)}}+\frac {33 a b (d \sec (e+f x))^{5/3}}{40 f}+\frac {3 b (d \sec (e+f x))^{5/3} (a+b \tan (e+f x))}{8 f} \end {gather*}
Antiderivative was successfully verified.
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Rule 2722
Rule 3567
Rule 3589
Rule 3857
Rubi steps
\begin {align*} \int (d \sec (e+f x))^{5/3} (a+b \tan (e+f x))^2 \, dx &=\frac {3 b (d \sec (e+f x))^{5/3} (a+b \tan (e+f x))}{8 f}+\frac {3}{8} \int (d \sec (e+f x))^{5/3} \left (\frac {8 a^2}{3}-b^2+\frac {11}{3} a b \tan (e+f x)\right ) \, dx\\ &=\frac {33 a b (d \sec (e+f x))^{5/3}}{40 f}+\frac {3 b (d \sec (e+f x))^{5/3} (a+b \tan (e+f x))}{8 f}+\frac {1}{8} \left (8 a^2-3 b^2\right ) \int (d \sec (e+f x))^{5/3} \, dx\\ &=\frac {33 a b (d \sec (e+f x))^{5/3}}{40 f}+\frac {3 b (d \sec (e+f x))^{5/3} (a+b \tan (e+f x))}{8 f}+\frac {1}{8} \left (\left (8 a^2-3 b^2\right ) \left (\frac {\cos (e+f x)}{d}\right )^{2/3} (d \sec (e+f x))^{2/3}\right ) \int \frac {1}{\left (\frac {\cos (e+f x)}{d}\right )^{5/3}} \, dx\\ &=\frac {33 a b (d \sec (e+f x))^{5/3}}{40 f}+\frac {3 \left (8 a^2-3 b^2\right ) d \, _2F_1\left (-\frac {1}{3},\frac {1}{2};\frac {2}{3};\cos ^2(e+f x)\right ) (d \sec (e+f x))^{2/3} \sin (e+f x)}{16 f \sqrt {\sin ^2(e+f x)}}+\frac {3 b (d \sec (e+f x))^{5/3} (a+b \tan (e+f x))}{8 f}\\ \end {align*}
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Mathematica [A]
time = 1.89, size = 108, normalized size = 0.91 \begin {gather*} \frac {(d \sec (e+f x))^{5/3} \left (15 \left (8 a^2-3 b^2\right ) \sin (2 (e+f x))-5 \left (8 a^2-3 b^2\right ) \sqrt [3]{\cos ^2(e+f x)} \, _2F_1\left (\frac {1}{3},\frac {1}{2};\frac {3}{2};\sin ^2(e+f x)\right ) \sin (2 (e+f x))+12 b (16 a+5 b \tan (e+f x))\right )}{160 f} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 0.32, size = 0, normalized size = 0.00 \[\int \left (d \sec \left (f x +e \right )\right )^{\frac {5}{3}} \left (a +b \tan \left (f x +e \right )\right )^{2}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int {\left (\frac {d}{\cos \left (e+f\,x\right )}\right )}^{5/3}\,{\left (a+b\,\mathrm {tan}\left (e+f\,x\right )\right )}^2 \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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